The calculated 'spin-only' magnetic moment of Ti2+ (3d2) is :
- 3.87 BM
- 4.90 BM
- 2.84 BM
- 5.92 BM
Answer
(3) 2.84 BM
Solution
Ti2+: [Ar] 3d2 ⇒ two unpaired electrons (Hund's rule), n = 2
= n(n+2) BM
= 2 4 = 8
≈ 2.84 BM
Answer: (3)
The calculated 'spin-only' magnetic moment of Ti2+ (3d2) is :
(3) 2.84 BM
Ti2+: [Ar] 3d2 ⇒ two unpaired electrons (Hund's rule), n = 2
= n(n+2) BM
= 2 4 = 8
≈ 2.84 BM
Answer: (3)
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