Let be the area of the region enclosed between the curves C1, C2, and the lines x= 1 and x= 4. Then the value of - 1 e ( -2 e- 2 ) is .
Answer
2.4 to 2.6
Solution
1=0, 2= 2, 3=2 , 4= 5 2.
ddx [e-x(1- x) ]=e-x( x+ x-1), so take F(x)=e-x(1- x).
x+ x-1 is >0 on (0, 2 ), <0 on ( 2,2 ), >0 on (2 , 5 2 ).
F(0)=0, F ( 2 )=e- /2, F(2 )=0, F ( 5 2 )=e-5 /2.
=e- /2+e- /2+e-5 /2 -2e- /2=e-5 /2.
- 1 e (e-5 /2 )= 52=2.5.
Answer: 2.5