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Sequences and Series · Question 25

JEE Main 2026 (Online) 24th January Evening ShiftMCQMedium📈 Topic in 19% papers+4−1
1

( 13 + 47 ) + ( 132 + 13 47 + 4272 ) + ( 133 + 132 47 + 13 4272 + 4373 ) + up to infinite terms, is equal to

  1. 74
  2. 43
  3. 65
  4. 52

Answer

(4) 52

Solution

The r-th bracket = m + n = r ( 13 )m ( 47 )n (m, n 0)

So the series contains every product ( 13 )m ( 47 )n exactly once, except m = n = 0 (the term 1).

S = ( m=0 13m ) ( n=0 ( 47 )n ) - 1

= 11 - 13 11 - 47 - 1

= 32 73 - 1

= 72 - 1 = 52

Answer: (4)

JEE Main 2026 (Online) 24th January Evening Shift

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2

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  1. 3
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  3. 7
  4. 12
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3

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  1. -26
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  3. -24
  4. -22
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JEE Main 2026 (Online) 22nd January Evening Shift
5

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6

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7

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  1. 3
  2. 6
  3. 9
  4. 12
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8

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  1. 2 - 1
  2. 2( 2 - 1)
  3. 2 - 2
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9

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  1. 23
  2. 14
  3. 18
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10

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  1. 18
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11

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