( 13 + 47 ) + ( 132 + 13 47 + 4272 ) + ( 133 + 132 47 + 13 4272 + 4373 ) + up to infinite terms, is equal to
- 74
- 43
- 65
- 52
Answer
(4) 52
Solution
The r-th bracket = m + n = r ( 13 )m ( 47 )n (m, n 0)
So the series contains every product ( 13 )m ( 47 )n exactly once, except m = n = 0 (the term 1).
S = ( m=0 13m ) ( n=0 ( 47 )n ) - 1
= 11 - 13 11 - 47 - 1
= 32 73 - 1
= 72 - 1 = 52
Answer: (4)