The energy that will be ideally radiated by a 100 kW transmitter in 1 hour is
- 36 107 J
- 36 104 J
- 36 105 J
- 1 105 J
Answer
(1) 36 107 J
Solution
Energy radiated = power time
E = Pt = (100 103 W) (3600 s)
= 3.6 108 J
= 36 107 J
Answer: (1)
The energy that will be ideally radiated by a 100 kW transmitter in 1 hour is
(1) 36 107 J
Energy radiated = power time
E = Pt = (100 103 W) (3600 s)
= 3.6 108 J
= 36 107 J
Answer: (1)
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