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Probability (Class 12) · Question 5

JEE Advanced 2024 Paper 1MCQEasy📈 Topic in 17% papers+4−1
1

A student appears for a quiz consisting of only true-false type questions and answers all the questions. The student knows the answers of some questions and guesses the answers for the remaining questions. Whenever the student knows the answer of a question, he gives the correct answer. Assume that the probability of the student giving the correct answer for a question, given that he has guessed it, is 12. Also assume that the probability of the answer for a question being guessed, given that the student’s answer is correct, is 16. Then the probability that the student knows the answer of a randomly chosen question is

  1. 112
  2. 17
  3. 57
  4. 512

Answer

(3) 57

Solution

Bayes' theorem. Let P(K)=p, P(G)=1-p; P(C|K)=1, P(C|G)= 12.

P(C)=p+ 1-p2= 1+p2

P(G|C)= (1-p)/2(1+p)/2= 1-p1+p= 16

6-6p=1+p p= 57

Answer: (C)

JEE Advanced 2024 Paper 1

Keep practising — Probability (Class 12)

2

Let X be a random variable, and let P(X=x) denote the probability that X takes the value x. Suppose that the points (x,P(X=x) ), x=0,1,2,3,4, lie on a fixed straight line in the xy-plane, and P(X=x)=0 for all x R-\0,1,2,3,4\. If the mean of X is 52, and the variance of X is , then the value of 24 is .

JEE Advanced 2024 Paper 1
3

A bag contains N balls out of which 3 balls are white, 6 balls are green, and the remaining balls are blue. Assume that the balls are identical otherwise. Three balls are drawn randomly one after the other without replacement. For i=1,2,3, let Wi, Gi, and Bi denote the events that the ball drawn in the ith draw is a white ball, green ball, and blue ball, respectively. If the probability P(W1 G2 B3)= 25N and the conditional probability P(B3 W1 G2)= 29, then N equals .

JEE Advanced 2024 Paper 2

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