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Probability (Class 12) · Question 6

JEE Advanced 2024 Paper 1NumericalMedium📈 Topic in 33% papers+4
1

Let X be a random variable, and let P(X=x) denote the probability that X takes the value x. Suppose that the points (x,P(X=x) ), x=0,1,2,3,4, lie on a fixed straight line in the xy-plane, and P(X=x)=0 for all x R-\0,1,2,3,4\. If the mean of X is 52, and the variance of X is , then the value of 24 is .

Answer

42

Solution

Let P(X=x)=mx+c, x=0,1,2,3,4.

P=10m+5c=1 and xP=30m+10c= 52

m= 120, c= 110: probabilities 0.10, 0.15, 0.20, 0.25, 0.30

E(X2)=0+0.15+0.8+2.25+4.8=8

=8- 254= 74 24 =42

Answer: 42

JEE Advanced 2024 Paper 1

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2

A bag contains N balls out of which 3 balls are white, 6 balls are green, and the remaining balls are blue. Assume that the balls are identical otherwise. Three balls are drawn randomly one after the other without replacement. For i=1,2,3, let Wi, Gi, and Bi denote the events that the ball drawn in the ith draw is a white ball, green ball, and blue ball, respectively. If the probability P(W1 G2 B3)= 25N and the conditional probability P(B3 W1 G2)= 29, then N equals .

JEE Advanced 2024 Paper 2

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