A cylindrical vessel of 40 cm radius is completely filled with water and its capacity is 528 dm3 (dm : decimeter). The vessel is placed on a solid block of exactly same height as vessel. If a small hole is made at 70 cm below the top of water level, then horizontal range of water falling on the ground in the beginning is cm.
- 120 2
- 140 2
- 140 3
- 120 3
Answer
(2) 140 2
Solution
[figure]
Capacity =528 dm3=0.528 m3
Height of vessel: H0= V r2= 0.528 227 (0.4)2= 0.528 722 0.16
⇒ H0=1.05 m =105 cm (the block is also 105 cm high)
Depth of the hole below the water surface: h=70 cm
Height of the hole above the ground: H=(105-70)+105=140 cm
Efflux speed v= 2gh; time to fall through H: t= 2Hg
⇒ Range x=vt=2 hH=2 70 140
∴ x=2 70 2=140 2 cm
Answer: (2)