A tub is filled with water and a wooden cube 10 cm 10 cm 10 cm is placed in the water. The wooden cube is found to float on the water with a part of it submerged in water. When a metal coin is placed on the wooden cube, the submerged part is increased by 3.87 cm. The mass of the metal coin is gram. (Take water density as 1 g/cm3 and density of wood as 0.4 g/cm3)
Answer
387
Solution
Initially (floating): submerged depth h= wood water 10=0.4 10=4 cm
With the coin the depth becomes 4+3.87=7.87 cm <10 cm, so the cube still floats.
Extra buoyant force = weight of coin:
mg= water (A h) g
m=1 (10 10) 3.87
=387 g
Answer: 387