A liquid drop of diameter 2 mm breaks into 512 droplets. The change in surface energy is 10-6 J. The value of is . (Take surface tension of liquid = 0.08 N/m)
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Answer
(2) 7
Solution
Big drop radius R=1 mm=10-3 m; volume is conserved:
512 43 r3= 43 R3 r= R8
Increase in area: A=512(4 r2)-4 R2
=4 R2 ( 51264-1 )=28 R2
E=T A=0.08 28 10-6
7.04 10-6 J
7
Answer: (2)