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Amines · Question 13

JEE Main 2026 (Online) 2nd April Evening ShiftNumericalMedium📈 Topic in 42% papers+4
1

Consider the following reactions sequence [figure] When the product (P) is subjected to Carius analysis using AgNO3, 1.0 g of the product (P) will produce g of the precipitate of AgBr. (Nearest Integer) (Given : molar mass in g mol-1 C : 12, H : 1, O : 16, N : 14, Br : 80, Ag : 108)

Answer

1

Solution

(i) Sn/HCl, then OH : –NO2 → –NH2 (p-toluidine)

(ii) (CH3CO)2O: –NH2 → –NHCOCH3 (activation is moderated, monosubstitution)

(iii) Br2/AlBr3: para position is blocked by –CH3; –NHCOCH3 is the stronger o/p director ⇒ Br enters ortho to –NHCOCH3

(iv) H3O : amide hydrolysed back to –NH2

⇒ P = 2-bromo-4-methylaniline [figure] , C7H8BrN

M(P) = 84 + 8 + 80 + 14 = 186 g mol-1; M(AgBr) = 188 g mol-1

1 mol P (1 Br) → 1 mol AgBr ⇒ mass of AgBr = 1.0186 188 = 1.01 g ≈ 1 g

Answer: 1

JEE Main 2026 (Online) 2nd April Evening Shift

Keep practising — Amines

2

Consider the following reactions giving major product. Identify the correct reaction.

  1. [figure]
  2. [figure]
  3. [figure]
  4. H3CCH2- O \|C-NH2 + Br2 + 4 KOH (alc) H3CCH2NH2 + 2KBr + K2CO3 + 2H2O
JEE Main 2026 (Online) 28th January Morning Shift
3

A student performed analysis of an aliphatic organic compound 'X' which on analysis gave C = 61.01%, H = 15.25%, N = 23.74%. This compound, on treatment with HNO2/H2O, produced another compound 'Y' which did not contain any nitrogen atom. However, the compound 'Y' upon controlled oxidation produced another compound 'Z' that responded to iodoform test. The structure of 'X' is :

  1. CH3-CH2CH(NH2)-CH3
  2. CH3CH2CH2NH2
  3. Ph-CH(CH3)-NH2
  4. [figure]
JEE Main 2026 (Online) 28th January Evening Shift
4

Total number of alkali-insoluble solid sulphonamides obtained by reaction of given amines with Hinsberg's reagent is . Aniline, N-Methylaniline, Methanamine, N,N-Dimethylmethanamine, N-Methylmethanamine, Phenylmethanamine, N-Propylaniline, N-Phenylaniline, N,N-Dimethylaniline, Allylamine, Isopropylamine

  1. 8
  2. 5
  3. 2
  4. 4
JEE Main 2026 (Online) 28th January Evening Shift
5

The correct stability order of the following diazonium salts is [figure]

  1. C > D > B > A
  2. A > C > D > B
  3. A > B > C > D
  4. C > A > D > B
JEE Main 2026 (Online) 24th January Morning Shift
6

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below

  1. Both Statement I and Statement II are false
  2. Statement I is false but Statement II is true
  3. Statement I is true but Statement II is false
  4. Both Statement I and Statement II are true
JEE Main 2026 (Online) 24th January Evening Shift
7

Consider the following sequence of reactions. [figure] Assuming that the reaction proceeds to completion, then 137 mg of 4-nitrotoluene will produce mg of B. (Given molar mass in g mol-1 H : 1, C : 12, N : 14, O : 16, Br : 80)

  1. 208
  2. 228
  3. 146
  4. 301
JEE Main 2026 (Online) 23rd January Morning Shift
8

Compound 'P' undergoes the following sequence of reactions : [figure] 'P' is :

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
JEE Main 2026 (Online) 23rd January Morning Shift
9

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below

  1. Both Statement I and Statement II are true
  2. Statement I is false but Statement II is true
  3. Statement I is true but Statement II is false
  4. Both Statement I and Statement II are false
JEE Main 2026 (Online) 23rd January Evening Shift
10

A student has been given a compound 'x' of molecular formula C6H7N. 'x' is sparingly soluble in water. However, on addition of dilute mineral acid, 'x' becomes soluble in water. 'x' when treated with CHCl3 and KOH(alc), 'y' is produced. 'y' has a specific unpleasant smell. On treatment with benzenesulphonyl chloride, 'x' gives a compound 'z' which is soluble in alkali. The number of different "H" atoms present in 'z' is :

  1. 8
  2. 4
  3. 5
  4. 7
JEE Main 2026 (Online) 23rd January Evening Shift
11

'A' is a neutral organic compound (M.F. : C8H9ON). On treatment with aqueous Br2/HO , 'A' forms a compound 'B' which is soluble in dilute acid. 'B' on treatment with aqueous NaNO2/HCl (0-5 C) produces a compound 'C' which on treatment with CuCN/NaCN produces 'D'. Hydrolysis of 'D' produces 'E' which is also obtainable from the hydrolysis of 'A'. 'E' on treatment with acidified KMnO4 produces 'F'. 'F' contains two different types of hydrogen atoms. The structure of 'A' is

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
JEE Main 2026 (Online) 22nd January Morning Shift

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