Amines · Question 20

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below

1. Both Statement I and Statement II are true
2. Statement I is false but Statement II is true
3. Statement I is true but Statement II is false
4. Both Statement I and Statement II are false

A student has been given a compound 'x' of molecular formula C6H7N. 'x' is sparingly soluble in water. However, on addition of dilute mineral acid, 'x' becomes soluble in water. 'x' when treated with CHCl3 and KOH(alc), 'y' is produced. 'y' has a specific unpleasant smell. On treatment with benzenesulphonyl chloride, 'x' gives a compound 'z' which is soluble in alkali. The number of different "H" atoms present in 'z' is :

1. 8
2. 4
3. 5
4. 7

'A' is a neutral organic compound (M.F. : C8H9ON). On treatment with aqueous Br2/HO , 'A' forms a compound 'B' which is soluble in dilute acid. 'B' on treatment with aqueous NaNO2/HCl (0-5 C) produces a compound 'C' which on treatment with CuCN/NaCN produces 'D'. Hydrolysis of 'D' produces 'E' which is also obtainable from the hydrolysis of 'A'. 'E' on treatment with acidified KMnO4 produces 'F'. 'F' contains two different types of hydrogen atoms. The structure of 'A' is

1. [figure]
2. [figure]
3. [figure]
4. [figure]

[figure] The final product [B] is :

1. [figure]
2. [figure]
3. [figure]
4. [figure]

The mass of benzanilide obtained from the benzoylation reaction of 5.8 g of aniline, if yield of product is 82\%, is g (nearest integer). (Given molar mass in g mol-1 H : 1, C : 12, N : 14, O : 16)

An organic compound (P) on treatment with aqueous ammonia under hot condition forms compound (Q) which on heating with Br2 and KOH forms compound (R) having molecular formula C6H7N. Names of P, Q and R respectively are.

1. Toluic acid, methylbenzamide, 2-methylaniline
2. Benzoic acid, benzamide, aniline
3. Benzoic acid, 4-methylbenzamide, 4-methylaniline
4. Phenylethanoic acid, phenylethanamide, benzamine

A hydrocarbon 'P' (C4H8) on reaction with HCl gives an optically active compound 'Q' (C4H9Cl) which on reaction with one mole of ammonia gives compound 'R' ( C4H11N). 'R' on diazotization followed by hydrolysis gives 'S'. Identify P, Q, R and S.

1. P=CH3-CH=CH-CH3, Q=CH3-CH2-CH2-CH2-Cl, R=CH3-CH2-CH2- NH2 |CH2, S=CH3-CH2- OH |CH2 |CH2
2. P=CH3-CH=CH-CH3, Q=CH3-CH2- Cl |CH-CH3, R=CH3-CH2- NH2 |CH-CH3, S=CH3-CH2- OH |CH-CH3
3. P = [figure] , Q = [figure] , R = [figure] , S = [figure]
4. P=CH3-CH2-CH=CH2, Q=CH3-CH2-CH2- Cl |CH2, R=CH3-CH2-CH2- CH3 |NH, S=CH3-CH2- OH | CH3 |CH

Consider the following reaction sequence [figure] The percentage of nitrogen in product 'T' formed is %. (Nearest integer) (Given molar mass in g mol-1 H : 1, C : 12, N : 14, O : 16)

[figure] Consider the above sequence of reactions. The number of bromine atom(s) in the final product (P) will be :

1. 6
2. 5
3. 1
4. 3

Which of the following amine(s) show(s) positive carbylamine test? Choose the correct answer from the options given below:

1. C Only
2. B, C and D Only
3. A and E Only
4. A and C Only