Light ray incident along a vector AO ( AO=2 i-3 j ) emerges out along vector OB ( OB=C i-4 j ) as shown in the figure below. The value of C is . [figure]
- 1.6
- 0.16
- 11.6
- 16
Answer
(1) 1.6
Solution
[figure]
The normal at O is along the y-axis; the angles and are measured from it
AO=2 i-3 j = 2 22+32= 2 13
OB=C i-4 j = C C2+16
Snell's law: 1 = 2
1 2 13=1.5 C C2+16
Squaring: 413= 2.25 C2C2+16
4C2+64=29.25 C2
C2= 6425.25 2.53
C 1.6
Answer: (1)