A spherical interface lens of radius R separates two media of refractive indices 1 and 1.4 respectively as shown in the figure below. A point source is placed at a distance of 4R in front of spherical interface. The magnitude of the magnification of point source image is . [figure]
- 1.66
- 2.33
- 2.66
- 1.33
Answer
(1) 1.66
Solution
[figure]
Light goes from n1=1 to n2=1.4; the centre of curvature lies in the denser medium.
Sign convention: u=-4R, radius =+R
n2v- n1u= n2-n1R
⇒ 1.4v+ 14R= 0.4R
⇒ 1.4v= 0.4-0.25R= 0.15R ⇒ v= 28R3
Magnification: m= n1vn2u= 1 28R31.4 (-4R)=- 53
∴ |m|= 53 1.66
Answer: (1)