The magnitude and direction of the acceleration produced in a body of mass 5 kg when two mutually perpendicular forces 8 N and 6 N act on it, are respectively :
- 2 m s-2; -1(3/4) with 8 N force
- 2 m s-2; -1(4/3) with 8 N force
- 2 m s-2; -1(3/4) with 6 N force
- 20 m s-2; -1(4/3) with 8 N force
Answer
(1) 2 m s-2; -1(3/4) with 8 N force
Solution
Resultant force F = 82 + 62 = 100 = 10 N
a = Fm = 105 = 2 m s-2, along the resultant force.
Angle θ of the resultant with the 8 N force: = 68 = 34
= -1(3/4) with the 8 N force
Answer: (1)