A ball of mass 0.5 kg is dropped from a height of 40 m. The ball hits the ground and rises to a height of 10 m. The impulse imparted to the ball during its collision with the ground is (Take g = 9.8 m/s2)
- 0
- 84 N s
- 21 N s
- 7 N s
Answer
(3) 21 N s
Solution
Speed just before impact: v1 = 2gh1 = 2 9.8 40 = 28 m/s (downward)
Speed just after impact: v2 = 2gh2 = 2 9.8 10 = 14 m/s (upward)
Impulse = m(v2 + v1) = 0.5 (14 + 28) = 21 N s
Answer: (3)