A horizontal force 10 N is applied to a block A as shown in figure. The mass of blocks A and B are 2 kg and 3 kg respectively. The blocks slide over a frictionless surface. The force exerted by block A on block B is : [figure]
- Zero
- 4 N
- 6 N
- 10 N
Answer
(3) 6 N
Solution
Common acceleration: a = FmA + mB = 102 + 3 = 2 m s-2
The only horizontal force on B is the push of A:
N = mB a = 3 2 = 6 N
Answer: (3)