PYQSide ExamsMy practice

Equilibrium · Question 8

JEE Main 2026 (Online) 5th April Morning ShiftNumericalMedium📈 Topic in 13% papers+4
1

The values of pressure equilibrium constant recorded at different temperatures for the following equilibrium reaction have been given below A(g) B(g) + C(g) array|c|c| 1T ( K-1) & 10 Kp \ 0.05 & 3.5 \ 0.06 & 2.5 \ 0.07 & 1.5 \ array The magnitude of H R calculated from the above data is . (Nearest integer)

Answer

230

Solution

van't Hoff equation: 10 Kp = - H 2.303R 1T + constant

⇒ A plot of 10 Kp vs 1T is a straight line of slope - H 2.303R

Slope = 1.5 - 3.50.07 - 0.05 = -20.02 = -100 K

(the three points lie on one line: each 0.01 rise in 1/T lowers log Kp by 1)

⇒ H 2.303R = 100

∴ H R = 230.3 230 K

Answer: 230

JEE Main 2026 (Online) 5th April Morning Shift

Keep practising — Equilibrium

2

The reaction A(g) B(g) + C(g) was initiated with the amount 'a' of A(g). At equilibrium it is found that the amount of A(g) remaining is (a − x) at a total pressure of p. The equilibrium constant Kp of the reaction can be calculated from the expression :

  1. x2a2 + x2 p
  2. x2a2 - x2 p
  3. a + x2x2 p
  4. a2 - x2x2 p
JEE Main 2026 (Online) 5th April Evening Shift
3

At T(K), the equilibrium constant of A2(g) + B2(g) C(g) is 2.7 10-5. What is the equilibrium constant for 13A2(g) + 13B2(g) 13C(g) at the same temperature?

  1. (2.7 10-5)3
  2. 6 10-2
  3. 2.7 10-5
  4. 3 10-2
JEE Main 2026 (Online) 4th April Morning Shift
4

The pH of a solution obtained by mixing 5 mL of 0.1 M NH4OH solution with 250 mL of 0.1 M NH4Cl solution is 10-2. (Nearest integer) Given: pKb(NH4OH) = 4.74 2 = 0.30 3 = 0.48 5 = 0.70

JEE Main 2026 (Online) 4th April Morning Shift
5

20 mL of a solution of acetic acid required 28.4 mL of 0.1 M NaOH for its neutralization. A solution (X) was prepared by mixing 20 mL of the above acetic acid and 14.2 mL of 0.1 M NaOH solution. What is the pH of the solution (X)? (pKa value of acetic acid is 4.75).

  1. 7.0
  2. 4.75
  3. 3.5
  4. 4.82
JEE Main 2026 (Online) 4th April Evening Shift
6

For the following reaction at 50 °C and at 2 atm pressure, 2N2O5(g) 2N2O4(g) + O2(g) N2O5 is 50% dissociated. The magnitude of standard free energy change at this temperature is x. x = J mol-1 [Nearest integer]. Given : R = 8.314 J mol-1 K-1, log 2 = 0.30, log 3 = 0.48, ln 10 = 2.303, °C + 273 = K

JEE Main 2026 (Online) 4th April Evening Shift
7

The solubility product constants of Ag2CrO4 and AgBr are 32x and 4y respectively at 298 K. The value of ( molarity of Ag2CrO4molarity of AgBr ) can be expressed as :

  1. 2 [3]xy
  2. 2 xy
  3. xy
  4. [3]x y
JEE Main 2026 (Online) 2nd April Morning Shift
8

The first and second ionization constants of a weak dibasic acid H2A are 8.1 10-8 and 1.0 10-13 respectively. 0.1 mol of H2A was dissolved in 1 L of 0.1 M HCl solution. The concentration of HA- in the resultant solution is:

  1. 0.1 M
  2. 9.53 10-6 M
  3. 8.1 10-8 M
  4. 1.0 10-13 M
JEE Main 2026 (Online) 2nd April Evening Shift
9

At 25°C, 20.0 mL of 0.2 M weak monoprotic acid HX is titrated against 0.2 M NaOH. The pH of the solution (a) at the start of the titration (when NaOH has not been added) and (b) when 10 mL of NaOH is added respectively, are : Given : Ka = 5 10-4 pKa = 3.3 1

  1. array|c|c| (a) & (b) \ 0.7 & 2.0 \ array
  2. array|c|c| (a) & (b) \ 2.0 & 3.3 \ array
  3. array|c|c| (a) & (b) \ 1.1 & 2.2 \ array
  4. array|c|c| (a) & (b) \ 3.0 & 2.2 \ array
JEE Main 2026 (Online) 2nd April Evening Shift
10

Consider a weak base 'B' of pKb = 5.699. 'x' mL of 0.02 M HCl and 'y' mL of 0.02 M weak base 'B' are mixed to make 100 mL of a buffer of pH 9 at 25 . The values of 'x' and 'y' respectively are : [Given : 2 = 0.3010, 3 = 0.4771, 5 = 0.699]

  1. arraycc x & y \ 42.7 & 57.3 array
  2. arraycc x & y \ 14.3 & 85.7 array
  3. arraycc x & y \ 85.7 & 14.3 array
  4. arraycc x & y \ 11.1 & 88.9 array
JEE Main 2026 (Online) 28th January Morning Shift
11

Consider the dissociation equilibrium of the following weak acid HA H+(aq) + A-(aq) If the pKa of the acid is 4, then the pH of 10 mM HA solution is . (Nearest integer) [Given: The degree of dissociation can be neglected with respect to unity]

JEE Main 2026 (Online) 28th January Morning Shift

All Equilibrium PYQs →

PDFDownload Equilibrium PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Chemistry chapters