Three rotten apples are accidentally mixed with fifteen good apples. Assuming the random variable x to be the number of rotten apples in a draw of two apples, the variance of x is
- 57153
- 40153
- 37153
- 47153
Answer
(2) 40153
Solution
x=0, 1, 2; total ways =18C2=153
P(0)= 15C2153= 105153, P(1)= 3 15153= 45153, P(2)= 3C2153= 3153
E(x)= 45+2 3153= 51153= 13, E(x2)= 45+4 3153= 57153
Var(x)=E(x2)-[E(x)]2= 57153- 19
= 57-17153= 40153
Answer: (2)