Match List I with List II Choose the correct answer from the options given below :
- (A)-(II), (B)-(IV), (C)-(I), (D)-(III)
- (A)-(I), (B)-(IV), (C)-(II), (D)-(III)
- (A)-(III), (B)-(II), (C)-(I), (D)-(IV)
- (A)-(IV), (B)-(II), (C)-(III), (D)-(I)
Answer
(1) (A)-(II), (B)-(IV), (C)-(I), (D)-(III)
Solution
(A): C6H5NH2 NaNO2 + HCl C6H5N2+Cl- H2O, warm C6H5OH (diazonium salt hydrolysed), so (A) is (II).
(B): acidified dichromate oxidises phenol to p-benzoquinone, so (B) is (IV).
(C): in the Reimer–Tiemann reaction –CHO enters ortho to –OH, giving salicylaldehyde, so (C) is (I).
(D): in Kolbe's reaction phenoxide takes up CO2; acidification gives salicylic acid, so (D) is (III).
Hence (A)-(II), (B)-(IV), (C)-(I), (D)-(III).
Answer: (1)