The major products formed : [figure] A and B respectively are :
- [figure]
- [figure]
- [figure]
- [figure]
Answer
(1) [figure]
Solution
[figure]
–OCH3 (+R) is o/p-directing; para product is major (ortho is crowded) ⇒ A = p-nitroanisole
In A, both free positions ortho to –OCH3 are also meta to –NO2 (directions agree)
∵ excess Br2 ⇒ both get Br ⇒ B = 2,6-dibromo-4-nitroanisole
Answer: (1)