A solution of sucrose (molar mass = 342 g mol-1) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The freezing point of the solution obtained will be (Kf for water = 1.86 K kg mol-1)
- -0.372 C
- -0.520 C
- +0.372 C
- -0.570 C
Answer
(1) -0.372 C
Solution
Molality, m = 68.5/3421 kg = 0.2 mol kg-1
Tf = Kf m = 1.86 0.2
= 0.372 K
Freezing point of solution = 0 - 0.372 = -0.372 C
Answer: (1)