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Application of Integrals · Question 25

JEE Main 2025 (Online) 3rd April Morning ShiftNumericalMedium📈 Topic in 6% papers+4
1

The area of the region bounded by the curve y = \|x|, x|x-2|\, the x-axis and the lines x = -2 and x = 4 is equal to

Answer

12

Solution

For -2 x < 0: x|x-2| < 0 < |x| y = -x

For 0 x 2: x(2-x) x x 1

y = 2x - x2 on [0, 1], y = x on [1, 2]

For 2 x 4: x(x-2) x x 3

y = x on [2, 3], y = x2 - 2x on [3, 4]

[figure]

Area = -20(-x) dx + 01(2x - x2) dx + 13x dx + 34(x2 - 2x) dx

= 2 + (1 - 13 ) + 9-12 + [ x33 - x2 ]34

= 2 + 23 + 4 + ( 163 - 0 )

= 12

Answer: 12

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2

The area of the region \(x, y) : |x - y| y 4 x\ is

  1. 5123
  2. 20483
  3. 512
  4. 10243
JEE Main 2025 (Online) 3rd April Evening Shift
3

If the area of the region \(x, y) : |4 - x2 | y x2, y 4, x 0 \ is ( 80 2 - ), , N, then + is equal to .

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4

Let the area of the region \(x, y) : 2y x2 + 3, y + |x| 3, y |x - 1|\ be A. Then 6A is equal to :

  1. 14
  2. 18
  3. 16
  4. 12
JEE Main 2025 (Online) 29th January Morning Shift
5

The area (in sq. units) of the region \(x, y) : 0 y 2|x| + 1, 0 y x2 + 1, |x| 3\ is

  1. 323
  2. 643
  3. 173
  4. 803
JEE Main 2025 (Online) 28th January Morning Shift
6

The area of the region bounded by the curves x(1 + y2) = 1 and y2 = 2x is:

  1. 4 - 13
  2. 2 - 13
  3. 2 ( 2 - 13 )
  4. 12 ( 2 - 13 )
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