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Application of Integrals · Question 24

JEE Main 2025 (Online) 4th April Evening ShiftMCQMedium📈 Topic in 16% papers+4−1
1

A line passing through the point A(-2, 0) touches the parabola P: y2 = x - 2 at the point B in the first quadrant. The area of the region bounded by the line AB, parabola P and the x-axis, is :

  1. 3
  2. 73
  3. 83
  4. 2

Answer

(3) 83

Solution

Let B = (t2 + 2, t), t > 0.

Tangent at B: 2yt = x + (t2 + 2) - 4, i.e. 2ty = x + t2 - 2

It passes through A(-2, 0): 0 = -2 + t2 - 2 t2 = 4 t = 2

B(6, 2); line AB: 4y = x + 2, i.e. x = 4y - 2

[figure]

Required area (strips parallel to the x-axis, 0 y 2):

= 02 [(y2 + 2) - (4y - 2) ] dy = 02 (y - 2)2 dy

= [ (y - 2)33 ]02 = 0 - (- 83 ) = 83

Answer: (3)

JEE Main 2025 (Online) 4th April Evening Shift

Keep practising — Application of Integrals

2

The area of the region bounded by the curve y = \|x|, x|x-2|\, the x-axis and the lines x = -2 and x = 4 is equal to

JEE Main 2025 (Online) 3rd April Morning Shift
3

The area of the region \(x, y) : |x - y| y 4 x\ is

  1. 5123
  2. 20483
  3. 512
  4. 10243
JEE Main 2025 (Online) 3rd April Evening Shift
4

If the area of the region \(x, y) : |4 - x2 | y x2, y 4, x 0 \ is ( 80 2 - ), , N, then + is equal to .

JEE Main 2025 (Online) 2nd April Morning Shift
5

Let the area of the region \(x, y) : 2y x2 + 3, y + |x| 3, y |x - 1|\ be A. Then 6A is equal to :

  1. 14
  2. 18
  3. 16
  4. 12
JEE Main 2025 (Online) 29th January Morning Shift
6

The area (in sq. units) of the region \(x, y) : 0 y 2|x| + 1, 0 y x2 + 1, |x| 3\ is

  1. 323
  2. 643
  3. 173
  4. 803
JEE Main 2025 (Online) 28th January Morning Shift
7

The area of the region bounded by the curves x(1 + y2) = 1 and y2 = 2x is:

  1. 4 - 13
  2. 2 - 13
  3. 2 ( 2 - 13 )
  4. 12 ( 2 - 13 )
JEE Main 2025 (Online) 28th January Evening Shift

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