A filament bulb (500 W, 100 V) is to be used in a 230 V main supply. When a resistance R is connected in series, it works perfectly and the bulb consumes 500 W. The value of R is
- 230
- 46
- 26
- 13
Answer
(3) 26
Solution
Resistance of bulb: Rb = V2P = 1002500 = 20
Rated current: I = PV = 500100 = 5 A
Total resistance = 2305 = 46
R = 46 - 20 = 26
Answer: (3)