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Current Electricity · Question 58

AIPMT 2014MCQEasy📈 Topic in 0% papers+4−1
1

A potentiometer circuit has been set up for finding the internal resistance of a given cell. The main battery, used across the potentiometer wire, has an emf of 2.0 V and a negligible internal resistance. The potentiometer wire itself is 4 m long. When the resistance R, connected across the given cell, has values of (i) infinity, (ii) 9.5 , the balancing lengths on the potentiometer wire are found to be 3 m and 2.85 m, respectively. The value of internal resistance of the cell is

  1. 0.25
  2. 0.95
  3. 0.5
  4. 0.75

Answer

(3) 0.5

Solution

With R = (open circuit) the balancing length l1 = 3 m corresponds to the emf; with R = 9.5 the balancing length l2 = 2.85 m corresponds to the terminal voltage.

r = R ( l1l2 - 1 )

= 9.5 ( 32.85 - 1 ) = 9.5 0.152.85

= 0.5

Answer: (3)

AIPMT 2014

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2

The resistances of the four arms P, Q, R and S in a Wheatstone's bridge are 10 ohm, 30 ohm, 30 ohm and 90 ohm, respectively. The e.m.f. and internal resistance of the cell are 7 volt and 5 ohm respectively. If the galvanometer resistance is 50 ohm, the current drawn from the cell will be

  1. 0.1 A
  2. 2.0 A
  3. 1.0 A
  4. 0.2 A
NEET 2013
3

The internal resistance of a 2.1 V cell which gives a current of 0.2 A through a resistance of 10 is

  1. 0.8
  2. 1.0
  3. 0.2
  4. 0.5
NEET 2013
4

A wire of resistance 4 is stretched to twice its original length. The resistance of stretched wire would be

  1. 8
  2. 16
  3. 2
  4. 4
NEET 2013
5

Two rods are joined end to end, as shown. Both have a cross-sectional area of 0.01 cm2. Each is 1 meter long. One rod is of copper with a resistivity of 1.7 10-6 ohm-centimeter, the other is of iron with a resistivity of 10-5 ohm-centimeter. [figure] How much voltage is required to produce a current of 1 ampere in the rods?

  1. 0.00145 V
  2. 0.0145 V
  3. 1.7 10-6 V
  4. 0.117 V
NEET 2013 (Karnataka)
6

A 12 cm wire is given a shape of a right angled triangle ABC having sides 3 cm, 4 cm and 5 cm as shown in the figure. The resistance between two ends (AB, BC, CA) of the respective sides are measured one by one. Their ratio is [figure]

  1. 9 : 16 : 25
  2. 27 : 32 : 35
  3. 21 : 24 : 25
  4. 3 : 4 : 5
NEET 2013 (Karnataka)
7

Ten identical cells connected in series are needed to heat a wire of length one meter and radius 'r' by 10 in time 't'. How many cells will be required to heat the wire of length two meter of the same radius by the same temperature in time 't' ?

  1. 20
  2. 30
  3. 40
  4. 10
NEET 2013 (Karnataka)
8

A cell having an emf and internal resistance r is connected across a variable external resistance R. As the resistance R is increased, the plot of potential difference V across R is given by

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
AIPMT 2012 (Mains)
9

The power dissipated in the circuit shown in the figure is 30 watts. The value of R is [figure]

  1. 20
  2. 15
  3. 10
  4. 30
AIPMT 2012 (Mains)
10

In the circuit shown the cells A and B have negligible resistances. For VA = 12 V, R1 = 500 and R = 100 the galvanometer (G) shows no deflection. The value of VB is [figure]

  1. 4 V
  2. 2 V
  3. 12 V
  4. 6 V
AIPMT 2012 (Prelims)
11

A ring is made of a wire having a resistance R0 = 12 . Find the points A and B, as shown in the figure, at which a current carrying conductor should be connected so that the resistance R of the sub circuit between these points is equal to 83 . [figure]

  1. l1l2 = 58
  2. l1l2 = 13
  3. l1l2 = 38
  4. l1l2 = 12
AIPMT 2012 (Prelims)

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