Consider two radiations of wavelengths 1. 1 = 2000 Å 2. 2 = 6000 Å The ratio of the energies of these two radiations ( E1E2 ) is (Nearest integer).
Answer
3
Solution
E = hc ⇒ E 1
∴ E1E2 = 2 1 = 60002000 = 3
Answer: 3
Consider two radiations of wavelengths 1. 1 = 2000 Å 2. 2 = 6000 Å The ratio of the energies of these two radiations ( E1E2 ) is (Nearest integer).
3
E = hc ⇒ E 1
∴ E1E2 = 2 1 = 60002000 = 3
Answer: 3
If shortest wavelength of hydrogen atom in Lyman series is x, then longest wavelength in Balmer series of He+ is:
Match the LIST-I with LIST-II
The Bohr radius of a hydrogen like species is 70.53 pm. The species and the stationary state (n) are respectively (Given : Hydrogen atom Bohr radius is 52.9 pm)
Arrange the following atomic orbitals of multi electron atoms in order of increasing energy. Choose the correct answer from the options given below:
Identify the correct statements from the following : Choose the correct answer from the options given below:
Which of the following statement(s) is/are true ? Choose the correct answer from the options given below :
What is the ratio of wave number of first line (lowest energy line) of Balmer series of H atomic spectrum to first line of its Brackett series?
Which of the following is correct set of 4 quantum numbers of 19th electron in Chromium (Atomic number = 24) in accordance with Aufbau principle?
The species having identical radii according to the Bohr's theory are : Choose the correct answer from the options given below :
What is the energy (in J atom-1) required for the following process ? Li2+(g) Li3+(g) + e- (Take the ionization energy for the H atom in the ground state as 2.18 10-18 J atom-1)