A particle is moving such that its position coordinates (x, y) are (2 m, 3 m) at time t = 0, (6 m, 7 m) at time t = 2 s and (13 m, 14 m) at time t = 5 s. Average velocity vector ( vav) from t = 0 to t = 5 s is
- 15 (13 i + 14 j )
- 73 ( i + j )
- 2 ( i + j )
- 115 ( i + j )
Answer
(4) 115 ( i + j )
Solution
vav = r t = r(5) - r(0)5 - 0
r = (13 - 2) i + (14 - 3) j = 11 i + 11 j
⇒ vav = 11 i + 11 j5
= 115 ( i + j ) m s-1
Answer: (4)