A projectile is fired from the surface of the earth with a velocity of 5 m s-1 and angle with the horizontal. Another projectile fired from another planet with a velocity of 3 m s-1 at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet (in m s-2) is (Given g = 9.8 m s-2)
- 3.5
- 5.9
- 16.3
- 110.8
Answer
(1) 3.5
Solution
Equation of trajectory: y = x - g x22u2 2
Identical trajectories at the same ⇒ gu2 is the same:
g'32 = 9.852
⇒ g' = 9 9.825
= 3.53 3.5 m s-2
Answer: (1)