Total number of stereo isomers possible for the given structure : [figure]
- 4
- 2
- 8
- 3
Answer
(3) 8
Solution
[figure]
Double bond a: each carbon has two different groups (CH3/Br and H/CH2), so it shows geometrical isomerism.
Double bond b: each carbon also has two different groups, so it shows geometrical isomerism too.
C* carries H, Br and two different carbon chains, so it is a chiral centre.
So there are 3 stereogenic units in an unsymmetrical molecule, hence
number of stereoisomers = 2n = 23 = 8
Answer: (3)