Which one of the following graphs accurately represents the plot of partial pressure of CS2 vs its mole fraction in a mixture of acetone and CS2 at constant temperature?
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Answer
(1) [figure]
Solution
As per NCERT, a mixture of acetone and CS2 shows positive deviation from Raoult's law: acetone–CS2 attractions are weaker than acetone–acetone and CS2–CS2 attractions, so molecules escape more easily.
The partial pressure of CS2 lies above the Raoult's law line p = xCS2 p CS2 and reaches p CS2 at xCS2 = 1.
When CS2 is very dilute it behaves as the solute, so near xCS2 = 0 its curve follows Henry's law (p = KH x, with KH > p CS2, a steeper straight line); near xCS2 = 1 it is the solvent and approaches Raoult's law.
Graph (1) shows exactly this single curve: tangent to the Henry's law line at the start, above the Raoult's law line, ending at p CS2.
Graph (2) shows negative deviation, graph (3) an ideal solution, and graph (4) the total and both partial pressures (not the plot asked).
Answer: (1)