If power dissipated in the 9 Ω resistor in the circuit shown is 36 watt, the potential difference across the 2 Ω resistor is [figure]
- 4 volt
- 8 volt
- 10 volt
- 2 volt
Answer
(3) 10 volt
Solution
For the 9 Ω resistor: P = V2R
36 = V29 V = 18 V
The 6 Ω resistor is in parallel, so it also has 18 V across it.
I9 = 189 = 2 A, I6 = 186 = 3 A
Current through the 2 Ω resistor = 2 + 3 = 5 A
Potential difference across 2 Ω = 5 2 = 10 V
Answer: (3)