The correct bond order in the following species is
- O2+ < O2- < O22+
- O2- < O2+ < O22+
- O22+ < O2+ < O2-
- O22+ < O2- < O2+
Answer
(2) O2- < O2+ < O22+
Solution
Bond order = 12(Nb - Na)
O2- (17 electrons): Nb = 10, Na = 7 ⇒ B.O. = 1.5
O2+ (15 electrons): Nb = 10, Na = 5 ⇒ B.O. = 2.5
O22+ (14 electrons): Nb = 10, Na = 4 ⇒ B.O. = 3
∴ O2- < O2+ < O22+
Answer: (2)