The collector current in a common base amplifier using n-p-n transistor is 24 mA. If 80% of the electrons released by the emitter is accepted by the collector, then the base current is numerically :
- 3 mA and entering the base
- 6 mA and leaving the base
- 3 mA and leaving the base
- 6 mA and entering the base
Answer
(4) 6 mA and entering the base
Solution
IC = 0.8 IE
IE = 240.8 = 30 mA
IB = IE - IC = 30 - 24 = 6 mA
In an n-p-n transistor, conventional current enters at the base and the collector and leaves at the emitter, the base current enters the base.
IB = 6 mA, entering the base.
Answer: (4)