The values of Kp for the reactions, X Y + Z ....(i) A 2B ....(ii) are in the ratio 9 : 1. If degree of dissociation of X and A be equal, then total pressure at equilibrium (i) and (ii) are in the ratio
- 36 : 1
- 1 : 1
- 3 : 1
- 1 : 9
Answer
(1) 36 : 1
Solution
Let degree of dissociation = α for both; total pressures P1 and P2.
(i) Moles: X = 1 − α, Y = α, Z = α; total = 1 + α
Kp1 = 2 P1(1- )(1+ ) = 2 P11- 2
(ii) Moles: A = 1 − α, B = 2α; total = 1 + α
Kp2 = (2 )2 P2(1- )(1+ ) = 4 2 P21- 2
⇒ Kp1 Kp2 = P14P2 = 91
∴ P1 : P2 = 36 : 1
Answer: (1)