The equilibrium constants of the following are N2 + 3H2 2NH3; K1 N2 + O2 2NO; K2 H2 + 12O2 H2O; K3 The equilibrium constant (K) of the reaction: 2NH3 + 52O2 2NO + 3H2O will be
- K2K33/K1
- K2K3/K1
- K23K3/K1
- K1K33/K2
Answer
(1) K2K33/K1
Solution
Required reaction = (reverse of reaction 1) + (reaction 2) + 3 × (reaction 3)
2NH3 N2 + 3H2; K = 1K1
N2 + O2 2NO; K = K2
3H2 + 32O2 3H2O; K = K33
Adding: 2NH3 + 52O2 2NO + 3H2O
As per NCERT, when reactions are added their equilibrium constants are multiplied.
∴ K = K2K33K1
Answer: (1)