Two balls with same mass and initial velocity, are projected at different angles in such a way that maximum height reached by first ball is 8 times higher than that of the second ball. T1 and T2 are the total flying times of first and second ball, respectively, then the ratio of T1 and T2 is
- 2 : 1
- 2 : 1
- 2 2 : 1
- 4 : 1
Answer
(3) 2 2 : 1
Solution
For a projectile with speed u at angle :
H = u2 2 2g and T = 2u g
T2 = 4u2 2 g2 = 8Hg, i.e. T H
T1T2 = H1H2 = 8 = 2 2
T1 : T2 = 2 2 : 1
Answer: (3)