A block of mass 100 kg slides over a distance of 10 m on a horizontal surface. If the co-efficient of friction between the surfaces is 0.4, then the work done against friction (in J) is :
- 3900
- 4500
- 4200
- 4000
Answer
(4) 4000
Solution
W=fk s= mg s
on a horizontal surface N=mg, so fk= mg.
W=0.4 100 10 10
=4000 J
Answer: (4)