In qualitative analysis, the metals of group I can be separated from other ions by precipitating them as chloride salts. A solution initially contains Ag+ and Pb2+ at a concentration of 0.10 M. Aqueous HCl is added to this solution until the Cl- concentration is 0.10 M. What will the concentrations of Ag+ and Pb2+ be at equilibrium ? ( Ksp for AgCl = 1.8 10-10, Ksp for PbCl2 = 1.7 10-5)
- [Ag+] = 1.8 10-7 M, [ Pb2+] = 1.7 10-6 M
- [Ag+] = 1.8 10-11 M, [ Pb2+] = 8.5 10-5 M
- [Ag+] = 1.8 10-9 M, [ Pb2+] = 1.7 10-3 M
- [Ag+] = 1.8 10-11 M, [ Pb2+] = 1.7 10-4 M
Answer
(3) [Ag+] = 1.8 10-9 M, [ Pb2+] = 1.7 10-3 M
Solution
At equilibrium [Cl-] = 0.10 M and both salts precipitate (ionic products 0.1 0.1 and 0.1 (0.1)2 exceed their Ksp).
For AgCl: Ksp = [Ag+][Cl-]
⇒ [Ag+] = 1.8 10-100.10
= 1.8 10-9 M
For PbCl2: Ksp = [ Pb2+][Cl-]2
⇒ [ Pb2+] = 1.7 10-5(0.10)2
= 1.7 10-3 M
Answer: (3)