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If I(m,n)= 01xm-1(1-x)n-1dx, m,n>0, then I(9,14)+I(10,13) is
(4) I(9,13)
Write 1=x+(1-x) in the integrand:
xm-1(1-x)n-1=xm(1-x)n-1+xm-1(1-x)n
I(m,n)=I(m+1,n)+I(m,n+1)
m=9, n=13: I(9,13)=I(10,13)+I(9,14)
Answer: (4)
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