MX is a sparingly soluble salt that follows the given solubility equilibrium at 298 K. MX(s) M+(aq) + X-(aq); Ksp = 10-10 If the standard reduction potential for M+(aq) + e- M(s) is ( E M+/M ) = 0.79 V, then the value of the standard reduction potential for the metal/metal insoluble salt electrode E X-/MX(s)/M is mV. (nearest integer) [Given: 2.303RTF = 0.059 V]
Answer
200
Solution
Electrode reaction: MX(s) + e- M(s) + X-(aq)
It is the sum of: M+ + e- M ( E M+/M) and MX(s) M+ + X- ( Ksp)
E X-/MX/M = E M+/M + 2.303RTF Ksp
= 0.79 + 0.059 10-10
= 0.79 - 0.59
= 0.20 V = 200 mV
Answer: 200