Which of the following complexes exhibits the highest paramagnetic behaviour? where gly = glycine, en = ethylenediamine and bpy = bipyridyl moieties. (At. nos. Ti = 22, V = 23, Fe = 26, Co = 27)
- [Co(ox)2(OH)2]-
- [Ti(NH3)6]3+
- [V(gly)2(OH)2(NH3)2]+
- [Fe(en)(bpy)(NH3)2]2+
Answer
(1) [Co(ox)2(OH)2]-
Solution
Paramagnetism increases with the number of unpaired electrons on the metal ion.
(1) [Co(ox)2(OH)2]-: x + 2(-2) + 2(-1) = -1 x = +5; Co5+ is 3d4; ox and OH- are weak field ligands (high spin) 4 unpaired electrons.
(2) [Ti(NH3)6]3+: Ti3+ is 3d1 1 unpaired electron.
(3) [V(gly)2(OH)2(NH3)2]+: x + 2(-1) + 2(-1) + 0 = +1 x = +5; V5+ is 3d0 0 unpaired electrons.
(4) [Fe(en)(bpy)(NH3)2]2+: Fe2+ is 3d6; en and bpy are strong field ligands, so the electrons pair up ( t2g6eg0) 0 unpaired electrons.
[Co(ox)2(OH)2]- has the most unpaired electrons and shows the highest paramagnetism.
Answer: (1)