[Cr(H2O)6]Cl3 (At. no. of Cr = 24) has a magnetic moment of 3.83 B.M. The correct distribution of 3d electrons in the chromium of the complex is
- 3d1xy, 3d1yz, 3d1z2
- 3d1(x2-y2), 3d1z2, 3d1xz
- 3d1xy, 3d1(x2-y2), 3d1yz
- 3d1xy, 3d1yz, 3d1xz
Answer
(4) 3d1xy, 3d1yz, 3d1xz
Solution
Oxidation state of Cr: x + 6(0) - 3 = 0 ⇒ x = +3
Cr3+: [Ar] 3d3
= n(n+2) = 3.83 B.M. ⇒ n = 3 unpaired electrons
In an octahedral field the d orbitals split into t2g ( dxy, dyz, dxz, lower energy) and eg ( dx2-y2, dz2, higher energy).
∴ The three electrons occupy the t2g set singly: t2g3 eg0, i.e. 3d1xy, 3d1yz, 3d1xz.
Answer: (4)