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Aldehydes, Ketones and Carboxylic Acids · Question 13

JEE Main 2026 (Online) 24th January Evening ShiftMCQMedium📈 Topic in 13% papers+4−1
1

The unsaturated ether on acidic hydrolysis produces carbonyl compounds as shown below :- [figure] Based on this, predict the solution/reagent that will help to distinguish "P" and "Q" obtained in the following reaction :- CH3-CH=CH-O- CH3 |C=CH2 [ ]H3O P + Q

  1. Saturated NaHSO3 solution
  2. Fehling solution
  3. Lucas reagent
  4. 2,4-DNP reagent

Answer

(2) Fehling solution

Solution

Each O–vinyl bond is hydrolysed and the vinyl carbon becomes a carbonyl carbon:

CH3-CH=CH-O- CH3 |C=CH2 [ ]H3O

CH3-CH2-CHO + CH3- O \|C-CH3

P = propanal (aldehyde), Q = propanone (ketone).

(1) Both an aldehyde and a methyl ketone form bisulphite addition products no distinction.

(2) Fehling solution: propanal gives a red-brown precipitate of Cu2O, propanone does not distinguishes.

(3) Lucas reagent is a test for alcohols neither responds.

(4) 2,4-DNP gives orange-yellow 2,4-DNP derivatives with both no distinction.

Answer: (2)

JEE Main 2026 (Online) 24th January Evening Shift

Keep practising — Aldehydes, Ketones and Carboxylic Acids

2

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below

  1. Statement I is true but Statement II is false
  2. Both Statement I and Statement II are false
  3. Both Statement I and Statement II are true
  4. Statement I is false but Statement II is true
JEE Main 2026 (Online) 24th January Evening Shift
3

Grignard reagent RMgBr (P) reacts with water and forms a gas (Q). One gram of Q occupies 1.4 dm3 at STP. (P) on reaction with dry ice in dry ether followed by H3O+ forms a compound (Z). 0.1 mole of (Z) will weigh g. (Nearest integer)

JEE Main 2026 (Online) 24th January Evening Shift
4

'x' is the product which is obtained from propanenitrile and stannous chloride in the presence of hydrochloric acid followed by hydrolysis. 'y' is the product which is obtained from the but-2-ene by the ozonolysis followed by hydrolysis. From the following, which product is not obtained when one mole of 'x' and one mole of 'y' react with each other in the presence of alkali followed by heating?

  1. 2-Methylpent-2-enal
  2. 2-Methylbut-2-enal
  3. 3-Methylbut-2-enal
  4. Pent-2-enal
JEE Main 2026 (Online) 23rd January Morning Shift
5

[figure] The correct sequence of reagents for the above conversion of X to Y is :

  1. (i) NaOH(aq), (ii) Jones reagent, (iii) H3O+
  2. (i) NaOEt, (ii) B2H6/H2O2, (iii) Jones reagent
  3. (i) Jones reagent, (ii) NaOEt, (iii) Hot KMnO4/KOH
  4. (i) B2H6/H2O2, (ii) NaOEt, (iii) Jones reagent
JEE Main 2026 (Online) 23rd January Morning Shift
6

Which of the following statements are TRUE about Haloform reaction? Choose the correct answer from the options given below :

  1. A, B & C Only
  2. A, C & E Only
  3. B, D & E Only
  4. A & C Only
JEE Main 2026 (Online) 23rd January Evening Shift
7

Iodoform test can differentiate between Choose the correct answer from the options given below :

  1. A, B & E Only
  2. A & D Only
  3. A & E Only
  4. B, C & E Only
JEE Main 2026 (Online) 23rd January Evening Shift
8

Consider the following reaction of benzene. [figure] In compound (Q), the percentage of oxygen is %. (Nearest integer)

JEE Main 2026 (Online) 23rd January Evening Shift
9

Match the LIST-I with LIST-II Choose the correct answer from the options given below :

  1. A-IV, B-III, C-II, D-I
  2. A-III, B-I, C-IV, D-II
  3. A-II, B-I, C-IV, D-III
  4. A-III, B-IV, C-I, D-II
JEE Main 2026 (Online) 22nd January Morning Shift
10

The compound A, C8H8O2 reacts with acetophenone to form a single product via cross-Aldol condensation. The compound A on reaction with conc. NaOH forms a substituted benzyl alcohol as one of the two products. The compound A is :

  1. 2-hydroxy acetophenone
  2. 4-hydroxy benzaldehyde
  3. 4-methyl benzoic acid
  4. 4-methoxy benzaldehyde
JEE Main 2026 (Online) 22nd January Evening Shift
11

An organic compound "P" of molecular formula C6H12O3 gives positive iodoform test but negative Tollens' test. When "P" is treated with dilute acid, it produces "Q". "Q" gives positive Tollens' test and also iodoform test. The structure of "P" is :

  1. H- O \|C-CH2-CH2- OCH3 |CH-OCH3
  2. CH3- O \|C- OCH3 |CH- OCH3 |CH2
  3. CH3- O \|C-CH2- OCH3 |CH-OCH3
  4. CH3- O \|C- OCH3 | OCH3 |C-CH3
JEE Main 2026 (Online) 21st January Morning Shift

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