Consider the reactions. (i) (CH3)2CH-CH2Br C2H5OH (CH3)2CH-CH2OC2H5 + HBr (ii) (CH3)2CH-CH2Br C2H5O- (CH3)2CH-CH2OC2H5 + Br- The mechanisms of reactions (i) and (ii) are respectively
- SN1 and SN2
- SN1 and SN1
- SN2 and SN2
- SN2 and SN1
Answer
(1) SN1 and SN2
Solution
(i) C2H5OH is a weak, neutral nucleophile and a polar protic solvent. The reaction is a solvolysis: the C–Br bond ionises first (slow step, assisted by the protic solvent) and the carbocation is then attacked by ethanol.
⇒ Reaction (i) follows the SN1 path.
(ii) C2H5O- is a strong, negatively charged nucleophile; it attacks the -CH2Br carbon from the back side in one step while Br- leaves (Williamson synthesis).
⇒ Reaction (ii) follows the SN2 path.
∴ The mechanisms are SN1 and SN2 respectively.
Answer: (1)