In Hardy-Weinberg equation, the frequency of heterozygous individual is represented by
- pq
- p2
- 2pq
- q2
Answer
(3) 2pq
Solution
Hardy–Weinberg equation: p2 + 2pq + q2 = 1 (binomial expansion of (p+q)2)
where p2 = frequency of homozygous dominant (AA), q2 = frequency of homozygous recessive (aa)
∴ 2pq = frequency of heterozygous individuals (Aa)
Answer: (3)