The moment of inertia of a uniform circular disc of radius R and mass M about an axis touching the disc at its diameter and normal to the disc
- 12MR2
- MR2
- 25MR2
- 32MR2
Answer
(4) 32MR2
Solution
Moment of inertia about the axis through the centre and normal to the disc: IC = 12MR2
The required axis is parallel to it and touches the rim at the end of a diameter, i.e. at distance R from the centre.
By the theorem of parallel axes:
I = IC + MR2 = 12MR2 + MR2
∴ I = 32MR2
Answer: (4)