Consider the function f:(0, ) R defined by f(x)=e- | ex |. If m and n be respectively the number of points at which f is not continuous and f is not differentiable, then m+n is
- 0
- 1
- 2
- 3
Answer
(2) 1
Solution
f(x)= casese ex=x, & 0<x<1\ e- ex= 1x, & x 1 cases
[figure]
Both pieces are continuous and both give 1 at x=1 no break m=0
At x=1: LHD =1, RHD =- 112=-1 corner n=1
m+n=0+1=1
Answer: (2)