A 100-turn closely wound circular coil of radius 5 cm has a magnetic field of 3.14 10-3 T at its centre. The current flowing through the coil, and the magnitude of the magnetic moment of this coil are, respectively : (Take 0 = 4 10-7 T m/A)
- 2.5 A, 20 A m2
- 2 A, 4 A m2
- 2.5 A, 2 A m2
- 2 A, 10 A m2
Answer
(3) 2.5 A, 2 A m2
Solution
Field at the centre: B = 0 NI2R
⇒ I = 2BR 0 N = 2 3.14 10-3 0.054 10-7 100
= 3.14 10-41.256 10-4 = 2.5 A
Magnetic moment: m = NI R2 = 100 2.5 3.14 (0.05)2
= 1.96 2 A m2
Answer: (3)