A condenser of capacity C is charged to a potential difference of V1. The plates of the condenser are then connected to an ideal inductor of inductance L. The current through the inductor when the potential difference across the condenser reduces to V2 is
- ( C(V1-V2)2L ) 12
- C (V12-V22 )L
- C (V12+V22 )L
- ( C (V12-V22 )L ) 12
Answer
(4) ( C (V12-V22 )L ) 12
Solution
In an ideal LC circuit the total energy is conserved:
12CV12 = 12CV22 + 12LI2
LI2 = C (V12 - V22 )
I = ( C (V12-V22 )L ) 12
Answer: (4)