In the ac circuit an alternating voltage e = 200 2 sin 100t volts is connected to a capacitor of capacity 1 . The r.m.s. value of the current in the circuit is
- 10 mA
- 100 mA
- 200 mA
- 20 mA
Answer
(4) 20 mA
Solution
erms = 200 2 2 = 200 V, = 100 rad s-1
XC = 1 = 1100 10-6 = 104
Irms = ermsXC = 200104 = 0.02 A
Irms = 20 mA
Answer: (4)